1.What would be the compound interest accrued on an amount of Rs 8000 at the rate of 15 p.c.p.a. in threeyears?A.Rs.4283B. Rs.4051C. Rs.4167D. Rs.4325E. None of these
2.What will be the compound interest accrued on an amount of Rs 16,500/- @ 14 p.c.p.a. at the end ofthree years?
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3.What will be the compound interest on a sum of Rs. 40,000 after 3 years at the rate of 11 p.c.p.a.?
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4.What will be the compound interest obtained on sum of Rs. 12000/- @ 8% per capita per annum for 2years.
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5.What would be the compound interest accrued on an amount of Rs 7,400 @ 13.5 p.c.p.a, at the end oftwo years? [rounded off to two digits after decimal]A. 2,136.87B. 2,306.81C. Rs 2,032.18D. Rs2,132.87 E. None of these
6.What would be the compound interest obtained on an amount of Rs 20,000 at the rate of 15 p.c.p.a. after4years?
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7.A man gets a simple interest of Rs 1,000 on a certain principal at the rate of 5 p.c.p.a. in 4 years. Whatcompound interest
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8.Find the Compound Interest on sum of amount 1434000/- @13for 3 years.%3
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9.Find the compound interest on a sum of amount of Rs. 4500 @ of 8% P.C.P.A. for 2 years?A.780B. 750C. 748.8D. 747E. None of these10At what rate of % the sum of amount Rs. 5000 becomes 6298.56 in 3 years?
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11. At what rate of interest certain sum of amount becomes 1.728 times in 3 years?
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12At what time a sum of amount of Rs. 4000 becomes 4630.50 @ of 5% P.C.P.A?
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13A certain sum of amount becomes 121in 5 yrs at compound interest. In how many yrs it becomes 383?A15 yrsB. 14 yrsC. 16 yrsD. 18 yrsE. None of these
14A certain sum of amount on C.I. becomes 4800 in 4 yrs and 6000 in 8 yrs at same rate %. Find the sum.15Find the Compound Interest on sum of amount 12000/- @ 8% P.C.P.A. for 1 years. If compound
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interest compounded ½ yearly.
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What would be the compound interest accrued on an amount of Rs. 4320 @ 13.5 p.c.p.a. at the end of two years? [Rounded off to two digits after decimal]
- Rs. 1234.12
- Rs. 1243.13
- Rs. 1254.13
- Rs. 1245.13
- None of these
Answer [Detailed Solution Below]
Option 4 : Rs. 1245.13
Free
SBI Clerk Prelims Full Test 1
100 Questions 100 Marks 60 Mins
We know the formula for compound interest-
\[\Rightarrow {\rm{CI}} = \left[ {{\rm{P}}\left\{ {{{\left[ {1 + \frac{{\rm{R}}}{{100}}} \right]}^t} - 1} \right\}} \right]\]
Where,
CI = Compound interest
P = Principal
R = Rate of interest
t = Time period
\[\Rightarrow {\rm{Required\;CI}} = \left[ {4320\left\{ {{{\left[ {1 + \frac{{13.5}}{{100}}} \right]}^2} - 1} \right\}} \right]\]
= 4320 × [1.1352 - 1] = Rs. 1245.132 ≈ Rs. 1245.13
∴ Required CI = Rs. 1245.13
Last updated on Sep 28, 2022
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