What is the smallest number by which 2916 will be divided so that the quotient is a perfect cube?

Step-by-step explanation:

Prime factorising 2916, we get,

2916=2×2×3×3×3×3×3×3

=2

2

×3

6

.

We know, a perfect cube has multiples of 3 as powers of prime factors.

Here, number of 2’s is 2 and number of 3’s is 6.

So we need to multiply another 2 in the factorization to make 2916 a perfect cube.

Hence, the smallest number by which 2916 must be multiplied to obtain a perfect cube is 2.

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Extra Questions for Class 8 Maths Chapter 7 Cubes and Cube Roots

Cubes and Cube Roots Class 8 Extra Questions Very Short Answer Type

Question 1.
Find the cubes of the following:
[a] 12
[b] -6
[c] \[\frac { 2 }{ 3 }\]
[d] \[\frac { -5 }{ 6 }\]
Solution:

Question 2.
Find the cubes of the following:
[a] 0.3
[b] 0.8
[c] .001
[d] 2 – 0.3
Sol.
[a] [0.3]3 = 0.3 × 0.3 × 0.3 = 0.027
[b] [0.8]3 = 0.8 × 0.8 × 0.8 = 0.512
[c] [0.001]3 = [0.001] × [0.001] × [0.001] = 0.000000001
[d] [2 – 0.3]3 = [1.7]3 = 1.7 × 1.7 × 1.7 = 4.913

Question 3.
Is 135 a perfect cube?
Solution:
Prime factorisation of 135, is:
135 = 3 × 3 × 3 × 5
We find that on making triplet, the number 5 does not make a group of the triplet.
Hence, 135 is not a perfect cube.

Question 4.
Find the cube roots of the following:
[a] 1728
[b] 3375
Solution:


Question 5.
Examine if [i] 200 [ii] 864 are perfect cubes.
Solution:
[i] 200 = 2 × 2 × 2 × 5 × 5
If we form triplet of equal factors, the number 2 forms a group of three whereas 5 does not do it.
Therefore, 200 is not a perfect cube.


[ii] We have 864 = 2 × 2 × 2 × 2 × 2
If we form triplet of equal factors, the number 2 and 3 form a group of three whereas another group of 2’s does not do so.
Therefore, 864 is not a perfect cube.

Question 6.
Find the smallest number by which 1323 may be multiplied so that the product is a perfect cube.
Solution:
1323 = 3 × 3 × 3 × 7 × 7
Since we required one more 7 to make a triplet of 7.
Therefore 7 is the smallest number by which 1323 may be multiplied to make it a perfect cube.

Question 7.
What is the smallest number by which 2916 should be divided so that the quotient is a perfect cube?
Solution:
Prime factorisation of
2916 = 2 × 2 × 3 × 3 × 3 × 3 × 3 × 3
Since we required one more 2 to make a triplet
Therefore, the required smallest number by which 2916 should be divided to make it a perfect cube is 2 × 2 = 4, i.e., 2916 ÷ 4 = 729 which is a perfect cube.

Question 8.
Check whether 1728 is a perfect cube by using prime factorisation. [NCERT Exemplar]
Solution:
Prime factorisation of 1728 is
1728 = 2 × 2 × 2 × 2 × 2 × 2 × 3 × 3 × 3
Since all prime factors can be grouped in triplets.
Therefore, 1728 is a perfect cube.

Question 9.
Using prime factorisation, find the cube root of 5832. [NCERT Exemplar]
Solution:

Question 10.


Solution:

Cubes and Cube Roots Class 8 Extra Questions Short Answers Type

Question 11.


Solution:

Question 12.
Find the cube roots of
[i] 4\[\frac { 12 }{ 125 }\]
[ii] -0.729
Solution:

Question 13.
Express the following numbers as the sum of odd numbers using the given pattern


Solution:

Question 14.
Observe the following pattern and complete the blank spaces.
13 = 1


Solution:





















Extra Questions for Class 8 Maths

NCERT Solutions for Class 8 Maths

What is the smallest by which 2916 should be divided so that quotient is a perfect cube?

Therefore, the required smallest number by which 2916 should be divided to make it a perfect cube is 2 × 2 = 4, i.e., 2916 ÷ 4 = 729 which is a perfect cube.

What is the perfect cube of 2916?

2916 doesn't have a perfect cube.

What is the smallest number by which we divide 6912 so that the quotient becomes a perfect cube find the cube root of the quotient?

Given: A number 6912 . To do: To find the smallest number by which 6912 must be divided so that the number formed is a perfect cube. Therefore, we should divide 6912 by 22=4 2 2 = 4 , the smallest number to get 1728 which is a cube of 12 .

What is the smallest number by which 8640 may be divided so that the question is a perfect cube?

Hence 5 is the smallest number by which 8640 must be divided so that the quotient is a perfect cube.

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